25 reviewed questions with answers and explanations.
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Question 2
Which of the following is a fundamental unit?
- Newton
- Watt
- Joule
- Second
Answer and explanation
D: Second
The second is the SI base unit of time. Newton, watt and joule are derived units built from kilogram, metre and second.
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Question 9
An engine supplies useful mechanical power P to keep a vehicle moving at constant speed v. What driving force does it provide?
- P/v
- v/2
- Pv
- P/v²
Answer and explanation
A: P/v
Mechanical power for a force along the direction of motion is P = Fv. Dividing by speed gives the engine’s driving force F = P/v.
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Question 13
What liquid-column height supports atmospheric pressure 102000 N/m² if liquid density is 2600 kg/m³ and g = 10 m/s²? Give the answer to two decimal places.
- 0.75m
- 0.76m
- 3.92m
- 39.23m.
Answer and explanation
C: 3.92m
Hydrostatic pressure is p = ρgh. Thus h = 102000/(2600 × 10) = 3.923… m, or 3.92 m to two decimal places.
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Question 15
A platinum wire has resistance 0.75 Ω at 0 °C and 1.05 Ω at 100 °C. Assuming linear variation, find its temperature when resistance is 0.90 Ω.
- 43.0 °C
- 50.0 °C
- 69.9 °C
- 87.0 °C
Answer and explanation
B: 50.0 °C
The 0–100 °C resistance change is 1.05 − 0.75 = 0.30 Ω. The measured rise is 0.90 − 0.75 = 0.15 Ω, half the interval. Temperature is therefore 50.0 °C.
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Question 17
A fixed amount of gas is cooled at constant volume without condensation. Its pressure decreases because its molecules
- Collide less frequently with the walls of the container.
- Have the same average kinetic energy
- Break up into smaller molecules
- Decrease in number.
Answer and explanation
A: Collide less frequently with the walls of the container.
Cooling lowers the molecules’ average kinetic energy and speed. At fixed volume they strike the walls less often and with less momentum change per collision, reducing the gas pressure.
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Question 18
A 1 kg copper block at 100 °C is placed on ice at 0 °C. Neglect heat loss. Find the mass melted to the nearest gram, using copper’s specific heat capacity 400 J/(kg·K) and ice’s latent heat of fusion 333 × 10³ J/kg.
- 60g
- 67g
- 120g
- 133g
Answer and explanation
C: 120g
The copper loses Q = mcΔT = 1 × 400 × 100 = 40000 J. This melts ice of mass Q/L = 40000/333000 = 0.12012… kg, or 120 g to the nearest gram.
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Question 19
At external pressure 750 mmHg, what change is needed to make pure water boil at 100 °C?
- Increase the external pressure
- Reduce the external pressure
- Heat more rapidly at the same pressure
- Reduce the external pressure by a quarter
Answer and explanation
A: Increase the external pressure
Pure water boils near 100 °C at about 760 mmHg. At 750 mmHg it boils slightly below 100 °C. Raising the external pressure to about 760 mmHg raises the boiling point to 100 °C.
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Question 20
In ordinary heat-transfer experiments, which statements are correct? I. Land and sea breezes are natural convection currents. II. Convection occurs in liquids or gases, rather than solids retaining their fixed shape. III. The vacuum gap in a thermos flask prevents heat transfer by convection only.
- I and II only
- II and III only
- I and III only
- I, II and III.
Answer and explanation
A: I and II only
Land and sea breezes arise from natural convection. In ordinary heat-transfer experiments, convection is bulk motion of a liquid or gas. A vacuum suppresses both conduction and convection across the gap, so III is false.
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Question 23
Geometrical shadows and eclipses result primarily from the
- Refraction of light
- Rectilinear propagation of light
- Diffraction of light
- Reflection of light
Answer and explanation
B: Rectilinear propagation of light
In a uniform medium, light travels approximately in straight lines. An opaque object blocks those paths and produces a shadow; an eclipse occurs when a celestial body blocks the light reaching another body or observer.
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Question 24
An object 3 cm high is placed vertically 10 cm in front of a concave mirror. Its image is 40 cm from the mirror. Find the magnitude of the image height.
- 0.75 cm
- 4.00 cm
- 8.00 cm
- 12.00 cm
Answer and explanation
D: 12.00 cm
The magnitude of magnification is image distance divided by object distance: 40/10 = 4. Therefore the image height has magnitude 4 × 3 = 12 cm.
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Question 27
What must be the distance between an object and a converging lens of focal length 20cm to produce an erect image two times the object height?
- 20cm
- 15cm
- 10cm
- 5cm
Answer and explanation
C: 10cm
An erect image from a converging lens is virtual: v = −2u. Substituting in 1/f = 1/u + 1/v gives 1/20 = 1/(2u). Hence u = 10 cm, inside the focal length.
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Question 29
In an uncorrected short-sighted eye, light rays from a point on a very distant object are focused
- In front of the retina
- On the retina by a converging lens
- Behind the retina by a diverging lens
- In front of the retina a distance 2F from the lens.
Answer and explanation
A: In front of the retina
In an uncorrected short-sighted eye, parallel rays from a distant object converge before reaching the retina. A diverging corrective lens reduces the eye system’s convergence so the focus moves back onto the retina.
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Question 30
Under white illumination, which primary colour does an ideal magenta surface absorb?
- Red and blue
- Green only
- Red and green
- Red only.
Answer and explanation
B: Green only
An ideal magenta surface reflects red and blue light and absorbs green. Under white illumination, the reflected red and blue combine to appear magenta.
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Question 31
In a resonance tube closed at one end, the first resonant air-column length is 20 cm for a 480 Hz tuning fork. Neglect end correction and find the speed of sound.
- 96 m/s
- 255 m/s
- 340 m/s
- 384 m/s
Answer and explanation
D: 384 m/s
At the first resonance of a tube closed at one end, L = λ/4. Thus λ = 4 × 0.20 = 0.80 m and v = fλ = 480 × 0.80 = 384 m/s.
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Question 33
An organ pipe closed at one end is 80 cm long. Neglect end correction. Find its fundamental frequency to the nearest hertz if sound speed is 340 m/s.
- 106 Hz
- 213 Hz
- 318 Hz
- 425 Hz
Answer and explanation
A: 106 Hz
For the fundamental of a pipe closed at one end, λ = 4L = 3.20 m. Frequency is 340/3.20 = 106.25 Hz, or 106 Hz to the nearest hertz.
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Question 35
An insulated body is at rest in electrostatic equilibrium with positive net charge. Which statements are true? I. Positive charge exceeds negative charge. II. It creates an electric field. III. It stores electrostatic energy relative to its discharged state. IV. It carries a steady electric current.
- I and IV only
- I and II only
- I, II and III only
- I, II, III and IV
Answer and explanation
C: I, II and III only
Positive net charge means there is more positive than negative charge, usually through an electron deficit. The charged body creates a field and stores electrostatic energy. At rest in electrostatic equilibrium, it carries no steady current.
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Question 36
Which of the following is a vector?
- Electric charge
- Electric field
- Electric potential difference
- Electric capacitance.
Answer and explanation
B: Electric field
Electric field is force per unit positive test charge, so it has both magnitude and direction. Electric charge, potential difference and capacitance are scalars.
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Question 37
Three identical cells, each of emf 1.5 V and internal resistance 1.0 Ω, are connected in parallel with matching polarity across a 2.67 Ω load. Find the load current to two decimal places.
- 0.26A
- 0.41A
- 0.50A
- 0.79A.
Answer and explanation
C: 0.50A
Identical cells in parallel retain emf 1.5 V and have internal resistance 1/3 Ω. The load current is 1.5/(2.67 + 1/3) = 0.4994… A, or 0.50 A to two decimal places.
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Question 38
In a uniform metre bridge, a 2.0 Ω standard resistor occupies the gap beside the 0 cm end. The balance point is 55.0 cm from that end. Find the resistance in the other gap to two decimal places.
- 1.10 Ohms
- 1.64 Ohms
- 2.44 Ohms
- 27.50 Ohms
Answer and explanation
B: 1.64 Ohms
For a uniform metre bridge, resistance ratio equals wire-length ratio at balance. With 2.0 Ω beside the 0 cm end, 2.0/R = 55/45. Thus R = 2.0 × 45/55 = 1.64 Ω to two decimal places.
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Question 39
The energy supplied by an electrical source per unit positive charge for a complete circuit is its
- Kinetic energy
- Potential difference
- Electromotive force
- Electrical energy
Answer and explanation
C: Electromotive force
Emf is the energy supplied by a source per unit charge passing through it. That energy is transferred around the complete circuit, including the source’s internal resistance. Its unit is the volt, or joule per coulomb.
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Question 41
Which of the following is an essential physical property of the wires used for making fuses?
- Low density
- High thermal conductivity
- Low electrical resistivity
- Low melting point.
Answer and explanation
D: Low melting point.
A fuse element must melt when excessive current heats it sufficiently. Melting opens the circuit and stops the sustained overcurrent. A suitably low melting point supports this protective action.
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Question 43
For the same transmitted power, using a higher voltage reduces energy lost in the transmission wires through
- Heat dissipation
- Production of eddy currents
- Excessive current discharged
- Excessive voltage discharged.
Answer and explanation
A: Heat dissipation
For the same transmitted power, increasing voltage reduces current because P = VI. Heating loss in the wires is I²R, so lowering current reduces heat dissipation.
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Question 45
A galvanometer with full-scale current 10 mA and coil resistance 30 Ω is converted to a 10 A ammeter. Which approximate resistor and connection are required?
- 0.03 ohms series resistor
- 0.03 ohms shunt resistor
- 9.99 ohms shunt resistor
- 9.99 ohms series resistor
Answer and explanation
B: 0.03 ohms shunt resistor
The full-scale coil voltage is 0.010 × 30 = 0.30 V. The shunt carries 10 − 0.010 = 9.99 A, so its resistance is 0.30/9.99 ≈ 0.03 Ω. It must be parallel to the coil.
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Question 47
What precaution should a manufacturer take to ensure that energy loss in a transformer is minimized?
- Make the windings from high-resistance wire
- Make the magnetic core from thin, electrically insulated metal sheets
- Use no magnetic material in the core
- Minimize flux linking the primary and secondary coils
Answer and explanation
B: Make the magnetic core from thin, electrically insulated metal sheets
A transformer core made from thin, electrically insulated metal laminations restricts large circulating eddy currents. This reduces unwanted heating in the core.
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Question 50
A photoemissive photocell works on the principle of
- A voltaic cell
- Emission of electrons by incident radiation
- Emission of protons by incident electrons
- A photographic plate
Answer and explanation
B: Emission of electrons by incident radiation
A photoemissive cell uses incident photons to release electrons from a photosensitive surface. Those electrons can be collected to produce a measurable current.
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