JAMB Chemistry 1998

28 reviewed questions with answers and explanations.

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Question 1

The addition of water to calcium oxide leads to

  1. a physical change
  2. a chemical change
  3. the formation of mixture
  4. an endothermic change.
Answer and explanation

B: a chemical change

Calcium oxide reacts with water to form calcium hydroxide: CaO + H₂O → Ca(OH)₂. Formation of a new substance makes it a chemical change. The reaction releases heat.

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Question 4

C₃H₈(g) + 5O₂(g) → 4H₂O(g) + 3CO₂(g). What volume of oxygen at STP is needed to burn 50 cm³ of propane measured at STP?

  1. 250 cm³
  2. 150 cm³
  3. 100 cm³
  4. 50 cm³
Answer and explanation

A: 250 cm³

The equation shows one mole, or one gas volume at equal conditions, of propane requires five of oxygen. Therefore 50 cm³ propane needs 5 × 50 = 250 cm³ oxygen.

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Question 5

30 cm³ of hydrogen is collected over water at 27 °C and total pressure 780 mmHg. Taking the given water-vapour pressure as 10 mmHg, calculate the dry hydrogen volume at 760 mmHg and 7 °C. Use T(K) = t(°C) + 273.

  1. 40.0 cm³
  2. 35.7 cm³
  3. 28.4 cm³
  4. 25.2 cm³
Answer and explanation

C: 28.4 cm³

The initial hydrogen partial pressure is 780 − 10 = 770 mmHg. Use absolute temperatures 300 K and 280 K: V₂ = 30 × (770/760) × (280/300) = 28.37 cm³, or 28.4 cm³.

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Question 7

Sulfur dioxide and methane are released simultaneously at opposite ends of a narrow tube under the same conditions. What is the ratio R(SO₂):R(CH₄)? [S = 32, O = 16, C = 12, H = 1]

  1. 4:1
  2. 2:1
  3. 1:2
  4. 1:4
Answer and explanation

C: 1:2

M(SO₂) = 32 + 2(16) = 64 g mol⁻¹ and M(CH₄) = 12 + 4 = 16 g mol⁻¹. Graham’s law gives R(SO₂)/R(CH₄) = √(16/64) = 1/2. Thus the rate ratio is 1:2.

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Question 9

An atom is shown with four occupied electron shells and two electrons in the outermost shell. When it combines with chlorine, which type of bond is formed?

  1. Covalent bond
  2. Electrovalent bond
  3. Hydrogen bond
  4. Coordinate bond
Answer and explanation

B: Electrovalent bond

The two outer electrons can be transferred to two chlorine atoms. This produces a metal cation and chloride anions, held together by electrostatic attraction: an ionic, or electrovalent, bond.

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Question 11

The lines in the hydrogen emission spectrum result from emission of

  1. Electrons from the atom
  2. Energy during proton transitions
  3. Energy during electron transitions
  4. Neutrons from the atom
Answer and explanation

C: Energy during electron transitions

An electron moving from a higher to a lower energy level emits a photon with energy equal to the level difference. Hydrogen’s discrete energy levels produce separate spectral lines.

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Question 13

Which property is used to separate nitrogen and oxygen by industrial fractional distillation of liquid air?

  1. Boiling point
  2. Density
  3. Rate of diffusion
  4. Solubility
Answer and explanation

A: Boiling point

Fractional distillation of liquid air separates nitrogen and oxygen because they have different boiling points. The more volatile nitrogen boils off before oxygen.

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Question 14

Excess phosphorus is burned in a gas jar of air. The residual gas passes through concentrated KOH solution and then concentrated H₂SO₄. Which gases are collected?

  1. Carbon dioxide, nitrogen and noble gases
  2. Nitrogen dioxide and noble gases
  3. Nitrogen and noble gases
  4. Carbon dioxide, nitrogen dioxide and noble gases
Answer and explanation

C: Nitrogen and noble gases

Burning excess phosphorus removes oxygen from the air. Potassium hydroxide absorbs carbon dioxide and other acidic oxides, and concentrated sulfuric acid removes water vapour. Nitrogen and the noble gases remain.

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Question 18

Soap lather is a colloid in which

  1. Liquid is dispersed in gas
  2. Solid is dispersed in liquid
  3. Gas is dispersed in liquid
  4. Liquid is dispersed in liquid
Answer and explanation

C: Gas is dispersed in liquid

Soap lather is a foam: bubbles of gas are dispersed through a liquid film. Thus its dispersed phase is gas and its continuous phase is liquid.

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Question 19

At 25 °C, what is the pH after mixing 100 cm³ of 0.1 mol dm⁻³ HCl with 100 cm³ of 0.2 mol dm⁻³ NaOH, assuming additive volumes?

  1. 1.3
  2. 7.0
  3. 9.7
  4. 12.7
Answer and explanation

D: 12.7

Initial amounts are 0.010 mol HCl and 0.020 mol NaOH. After neutralisation, 0.010 mol OH⁻ remains in 0.200 dm³, so [OH⁻] = 0.050 mol dm⁻³. pOH = 1.30 and pH = 14.00 − 1.30 = 12.70.

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Question 21

What volume of 0.1 mol dm⁻³ sulfuric acid is needed to react completely with 2.86 g of sodium carbonate decahydrate, Na₂CO₃·10H₂O? [Na = 23, C = 12, H = 1, O = 16]

  1. 20 cm³
  2. 40 cm³
  3. 80 cm³
  4. 100 cm³
Answer and explanation

D: 100 cm³

M(Na₂CO₃·10H₂O) = 106 + 180 = 286 g mol⁻¹. The sample contains 2.86/286 = 0.0100 mol carbonate. H₂SO₄ reacts with carbonate in a 1:1 ratio, so the required volume is 0.0100/0.100 = 0.100 dm³ = 100 cm³.

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Question 23

What mass of gold is deposited from gold(III) sulfate when 15 A passes for 193 s, assuming full current efficiency? [Au = 197; F = 96,500 C mol⁻¹]

  1. 1.97 g
  2. 3.94 g
  3. 5.91 g
  4. 19.70 g
Answer and explanation

A: 1.97 g

The charge is Q = It = 15 × 193 = 2895 C, equivalent to 0.0300 mol electrons. Gold(III) needs three electrons per atom, so 0.0100 mol gold is deposited. Its mass is 0.0100 × 197 = 1.97 g.

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Question 24

Fe(s) + Cu²⁺(aq) → Fe²⁺(aq) + Cu(s). Which statement follows?

  1. Fe is the oxidising agent
  2. Fe is reduced
  3. Cu²⁺ loses electrons
  4. Cu²⁺ is the oxidising agent
Answer and explanation

D: Cu²⁺ is the oxidising agent

Cu²⁺ gains two electrons to form copper, so it is reduced. The substance that accepts electrons and causes the other substance to be oxidised is the oxidising agent.

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Question 25

In 2FeCl₂(s) + Cl₂(g) → 2FeCl₃(s), which is the reducing agent?

  1. FeCl₂
  2. Cl₂
  3. FeCl₃
  4. Fe
Answer and explanation

A: FeCl₂

Iron changes from +2 in FeCl₂ to +3 in FeCl₃. FeCl₂ is therefore oxidised and supplies the electrons that reduce chlorine, making it the reducing agent.

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Question 29

An energy diagram for P₂ + Q₂ → 2PQ places reactants at 10 kJ, products at 15 kJ and the peak at 40 kJ. What is the activation energy for the backward reaction?

  1. +5 kJ
  2. +15 kJ
  3. +25 kJ
  4. +30 kJ
Answer and explanation

C: +25 kJ

For the backward reaction, the starting energy is the product level, 15 kJ. The peak is 40 kJ, so the backward activation energy is 40 − 15 = 25 kJ.

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Question 30

For 2X(g) + Y(g) → Z(g), the rate of formation of Z is independent of [Y] and quadruples when [X] doubles. Which rate law agrees?

  1. R = k[X][Y]
  2. R = k[X]²[Y]
  3. R = k[X]²[Y]²
  4. R = k[X]²[Y]⁰
Answer and explanation

D: R = k[X]²[Y]⁰

Independence from [Y] means order zero in Y. Doubling [X] multiplies the rate by four, so 2ⁿ = 4 and n = 2. Therefore R = k[X]²[Y]⁰ = k[X]².

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Question 31

2Cl₂(g) + 2H₂O(g) ⇌ 4HCl(g) + O₂(g), ΔH° = +115 kJ mol⁻¹. How does decreasing temperature affect the equilibrium?

  1. Favours the reverse reaction
  2. Favours the forward reaction
  3. Has no effect on equilibrium
  4. Doubles the rate of the reverse reaction
Answer and explanation

A: Favours the reverse reaction

The positive ΔH means the forward reaction absorbs heat. Cooling favours the exothermic reverse direction, shifting the equilibrium towards chlorine and water vapour.

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Question 32

Consider: (i) 3CuO(s) + 2NH₃(g) → 3Cu(s) + 3H₂O(l) + N₂(g); (ii) 2NH₃(g) + 3Cl₂(g) → 6HCl(g) + N₂(g); (iii) 4NH₃(g) + 3O₂(g) → 6H₂O(l) + 2N₂(g). Which property of ammonia do these reactions demonstrate?

  1. Basic properties
  2. Acidic properties
  3. Reducing properties
  4. Oxidising properties
Answer and explanation

C: Reducing properties

Nitrogen in NH₃ has oxidation number −3 and becomes 0 in N₂ in each equation. Ammonia is oxidised while the other reactant is reduced, demonstrating that ammonia acts as a reducing agent.

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Question 35

A heated flask contains solution X. A delivery tube carries the gas from the flask into an inverted water-filled receiver, where nitrogen gas (N₂) is collected over water. Which mixture could X contain?

  1. Sodium nitrate and ammonium chloride
  2. Sodium nitrite and ammonium chloride
  3. Lead(II) nitrate and copper turnings
  4. Potassium nitrate and copper turnings
Answer and explanation

B: Sodium nitrite and ammonium chloride

On warming, sodium nitrite and ammonium chloride produce nitrogen: NaNO₂ + NH₄Cl → NaCl + N₂ + 2H₂O. The ammonium and nitrite ions together supply the two nitrogen atoms. Nitrogen is only slightly soluble in water, allowing collection by displacement of water. Nitrate and nitrite are different ions, NO₃⁻ and NO₂⁻ respectively.

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Question 37

What is observed when aqueous iron(III) chloride is mixed with aqueous sodium hydroxide?

  1. A gas is evolved
  2. A deep blue precipitate forms
  3. The resulting solution turns green
  4. A brown precipitate forms
Answer and explanation

D: A brown precipitate forms

Iron(III) ions form insoluble, reddish-brown iron(III) hydroxide: Fe³⁺(aq) + 3OH⁻(aq) → Fe(OH)₃(s). Iron remains in oxidation state +3; this is precipitation, not reduction to iron(II). Sodium and chloride ions remain in solution.

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Question 40

Why are alloys often preferred to pure metals for practical applications?

  1. Pure metals are too hard
  2. Pure metals are ductile
  3. Useful metallic properties can be improved by alloying
  4. All alloys are mixtures only of metals
Answer and explanation

C: Useful metallic properties can be improved by alloying

Alloying can improve properties needed for a use, such as hardness, strength or corrosion resistance. This is why a suitable alloy may be chosen over a pure metal; the improvement depends on the alloy and application.

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Question 41

What is the IUPAC name of CH₃CH₂CH(OH)CH(CH₃)₂?

  1. 4-Methylpentan-3-ol
  2. 2-Methylpentan-3-ol
  3. 3-Methylpentan-3-ol
  4. 1,1-Dimethylbutan-2-ol
Answer and explanation

B: 2-Methylpentan-3-ol

The longest chain containing the OH group has five carbons. The OH group is at carbon 3 whichever end is used, so choose the direction that gives the methyl substituent position 2 rather than 4. The name is 2-methylpentan-3-ol.

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Question 43

Ethene undergoes addition polymerisation with oxygen used as an initiator: nCH₂=CH₂ → [–CH₂–CH₂–]ₙ. Which material is produced?

  1. Rubber
  2. Polythene
  3. Polystyrene
  4. Butane
Answer and explanation

B: Polythene

Ethene monomers join by addition polymerisation. Their double bonds open to form the repeating unit –CH₂–CH₂–, giving polyethene, commonly called polythene.

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Question 45

What are the products of complete combustion of a pure hydrocarbon in excess oxygen?

  1. Carbon and hydrogen
  2. Carbon and water
  3. Carbon monoxide and hydrogen
  4. Carbon dioxide and water
Answer and explanation

D: Carbon dioxide and water

Complete combustion converts the carbon atoms of a hydrocarbon into carbon dioxide and its hydrogen atoms into water. Excess oxygen supports complete rather than incomplete combustion.

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Question 47

Cracking medicinal paraffin produces a gas that gives a pop with a lighted splint and an oily liquid that decolourises bromine solution. Which listed pair matches these observations?

  1. Carbon dioxide and an alkyne
  2. Carbon monoxide and an alkene
  3. Hydrogen and an alkene
  4. Hydrogen and an alkane
Answer and explanation

C: Hydrogen and an alkene

The gas that gives a pop with a lighted splint is hydrogen. The oily product decolourises bromine by addition at carbon–carbon unsaturation, consistent with an alkene from cracking. The matching pair is hydrogen and alkene.

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Question 48

Which formula represents an aromatic compound?

  1. C₆H₁₃OH
  2. C₆H₁₃Cl
  3. C₆H₅OH
  4. C₆H₁₄
Answer and explanation

C: C₆H₅OH

C₆H₅OH represents phenol, with an OH group attached to a benzene ring. That aromatic ring distinguishes it from the saturated aliphatic compounds listed.

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Question 49

Terylene is formed from ethane-1,2-diol and benzene-1,4-dicarboxylic acid by which type of polymer-forming reaction?

  1. Addition
  2. Condensation
  3. Elimination
  4. Substitution
Answer and explanation

B: Condensation

The diol and dicarboxylic acid form ester links while eliminating small water molecules. Repeated condensation produces the polyester Terylene.

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Question 50

Which statement is true of benzene and hexane under suitable reaction conditions?

  1. Both undergo substitution reactions
  2. Both characteristically undergo addition reactions
  3. Both are solids at room temperature
  4. Both readily decolourise bromine water in the ordinary unsaturation test
Answer and explanation

A: Both undergo substitution reactions

Both can undergo substitution under suitable conditions. Benzene undergoes electrophilic substitution, such as nitration, while hexane undergoes radical substitution with halogens under light. Both are liquids at room temperature.

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